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7. Reverse Integer

· 閱讀時間約 1 分鐘

Given a signed 32-bit integer x, return xwith its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

Input: x = 123 Output: 321

Example 2:

Input: x = -123 Output: -321

Example 3:

Input: x = 120 Output: 21

Constraints:

  • -231 <= x <= 231 - 1
class Solution {
public:
int reverse(int x) {
int reversed = 0;
while(x != 0) {
int digit = x % 10;
x /= 10;
if(reversed > INT_MAX / 10 || (reversed == INT_MAX / 10 && digit > INT_MAX % 10))
return 0;
if(reversed < INT_MIN / 10 || (reversed == INT_MIN / 10 && digit < INT_MIN % 10))
return 0;
reversed = reversed * 10 + digit;
}
return reversed;
}
};
  • T: $O(\log N)$
  • S: $O(1)$